Anyone here a math genius?

[Trip]

This is what I got

y^x=3y-1

x= (ln(3y-1)/ln(y)) only if y > 1/3

z=3^x+5

z = (3y-1)^(ln(3)/ln(y))+5

So basically we have two equations and 3 unknowns.

[Amber Lamps]

Originally Posted by Trip

yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.

What's wrong with my answer?

[Trip]

Originally Posted by Amber Lamps

What's wrong with my answer?

because without more info there is infinite solutions.

[EpyonXero]

Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.

[Amber Lamps]

Originally Posted by Trip

because without more info there is infinite solutions.

Aw shucks...

I really want this to be

yx=3y-1 solve for 3x+5

y=1
x=2

solution=11

[DLIT]

Every now and again I like to look in these threads to make myself feel dumb. Success.

[Amber Lamps]

Originally Posted by EpyonXero

Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.

Yea I know... I still think that this is some kind of misprint or something...

[Particle Man]

Originally Posted by DLIT

Every now and again I like to look in these threads to make myself feel dumb. Success.

Same here

There's a reason I was an English major

[racedoll]

Sounds like you need to get more info from her before any of us can solve it.

[Amber Lamps]

Originally Posted by racedoll

Sounds like you need to get more info from her before any of us can solve it.

Hey, I've solved it twice!